Evaluate the limits
LimLimLim
Xto + sum to infinity
5xcube-2xsquared +1 divide by 1-3x
We need to find,
limx→∞5x3−2x21−3x\lim_{x \to \infty} \frac{5x^3-2x^2}{1-3x}limx→∞1−3x5x3−2x2
The highest power of the x is 3.
When we find limx→∞\lim_{x \to \infty}limx→∞ we need to find the ratio of the coefficients of the highest power in numerator and denominator.
Here, limx→∞5x3−2x21−3x=50=∞\lim_{x \to \infty} \frac{5x^3-2x^2}{1-3x} = \frac{5}{0 } = \inftylimx→∞1−3x5x3−2x2=05=∞
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