Find the volume of the solid revolution generated by rotating the curve y = x² bounded by x = 3 and y = 0; about the y-axis
V=∫032πx×(x2)dx=V = \int_{0}^{3} 2\pi x\times(x^2 ) dx =V=∫032πx×(x2)dx=
=2π∫03x3dx=2π[x44]∣03= 2\pi \int_{0}^{3} x^3 dx = 2\pi [\frac{x^4}{4} ] \Big\vert_{0}^{3}=2π∫03x3dx=2π[4x4]∣∣03
=2π[814−0]=2π[814]=81π2= 2\pi [\frac{81}{4}-0] = 2\pi [\frac{81}{4}] = \frac{81 \pi}{2}=2π[481−0]=2π[481]=281π
Answer
V=81π2V = \frac{81\pi}{2}V=281π
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