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Answer to Question #185835 in Calculus for kaye
Question #185835
π(π₯) = π₯
3 β 3π₯
2
, π₯ β [1, 3]
Expert's answer
"f(x) = x + \\frac{3 - 3x}{2}\\\\\n\n\n\nf'(x) = 1 - \\frac{3}{2} = -\\frac{1}{2}"
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