𝑓(𝑥) = 𝑥
3 − 3𝑥
2
, 𝑥 ∈ [1, 3]
f(x)=x+3−3x2f′(x)=1−32=−12f(x) = x + \frac{3 - 3x}{2}\\ f'(x) = 1 - \frac{3}{2} = -\frac{1}{2}f(x)=x+23−3xf′(x)=1−23=−21
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