Answer to Question #185783 in Calculus for kaye

Question

𝒉(𝒙) = 𝐥𝐨𝐠𝟒

(𝟐𝒙

𝟑 − 𝟑)

Answer 1

$$h(x)=\log_4(2x^3-3)$$

$$h'(x)=(\log_4(2x^3-3))'=(\dfrac{\ln(2x^3-3)}{\ln4})'$$

$$=\dfrac{6x^2}{(2x^3-3)\ln4}$$