Answer to Question #185782 in Calculus for kaye

Question

𝒄(𝒙) = 𝐥𝐧 𝒙

𝟑 − 𝟒

Answer 1

Ans:-

$c(x)=lnx^3-4$

$\Rightarrow c(x)= 3\times lnx -4$

We know that $lnx=(x-1)-\dfrac{(x-1)^2}{2}+\dfrac{(x-1)^3}{3}-\dfrac{(x-1)^4}{4}+........$

So

$\Rightarrow$ $c(x)=3\times[(x-1)-\dfrac{(x-1)^2}{2}+\dfrac{(x-1)^3}{3}-\dfrac{(x-1)^4}{4}+........]-4$