Find the equation for circle with center (1,3) that passes through (4, -1).
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Expert's answer
2012-11-12T11:34:33-0500
The equation of the circle is (x-a)^2+(y-b)^2=r^2, where (a,b) - coordinates of the centre and r - radius of the circle. Then (4-1)^2+(-1-3)^2=r^2 25=r^2 then r=5 Finally the equation of the given circle is (x-1)^2+(y-3)^2=25
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