Question

y = e^sin x tanh^-1 (4x^2)

find dy/dx

Answer 1

For the function $y = e^{\sin x} \tanh^{-1} (4x^2)$ let us find $\frac{dy}{dx}:$

$\frac{dy}{dx}=e^{\sin x}\cos x\tanh^{-1} (4x^2)+e^{\sin x}\frac{8x}{1-16x^4}.$