f(x) = (archtanh √3x^2)^3
"\\displaystyle\nf(x) = (\\mathrm{archtanh}(\\sqrt{3x^2}))^3\\\\\n\n\\begin{aligned}\nf'(x) &= 3(\\mathrm{archtanh}(\\sqrt{3}x))^2 \\times \\sqrt{3} \\times \\frac{1}{1 - 3x^2} \n\\\\&= \\frac{3\\sqrt{3}(\\mathrm{arctanh}(\\sqrt{3x^2}))^2}{1 - 3x^2} \n\\end{aligned}"
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