Differentiate y with respect to X and hence find the gradient of the tangent to the curve
y=4x2 + 3x +2 when x=2
y′=8x+3Gradient at x=2 is 8(2)+3=19.y' = 8x + 3\\ \textsf{Gradient at }\,\, x = 2 \,\, \textsf{is}\,\,8(2) + 3 = 19.y′=8x+3Gradient at x=2is8(2)+3=19.
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