evaluate limx-0(n/1+n^2+n/4+n^2+n/9+n^2+.....+n/2n^2)
limn→0(n1+n2+n4+n2+n9+n2+.....+n2n2)lim_{n\rightarrow0}(\dfrac{n}{1+n^2}+\dfrac{n}{4+n^2}+\dfrac{n}{9+n^2}+.....+\dfrac{n}{2n^2})limn→0(1+n2n+4+n2n+9+n2n+.....+2n2n)
The value of all the terms in given limit is 0 except last term
⇒limn→012n\Rightarrow lim_{n\rightarrow 0}\dfrac{1}{2n}⇒limn→02n1
=10=∞=\dfrac{1}{0}=\infty=01=∞
Hence The given limit does not exist.
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