The function f has a continuous second derivative, and it satisfies f(−1)=−3, f′(−1)=0 and f′′(−1)=1.
We can conclude that
A. f has neither a local maximum nor a local minimum at -1
B. f has a local maximum at -1
C. f has a local minimum at -1
D. We cannot determine if A, B, or C hold without more information.
1
Expert's answer
2012-11-02T10:19:09-0400
f′(−1)=0 then x=-1 can be a local extremum f"(-1)=1>0 then f concave down so it is the pointof local minimum correct answer B
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