Answer to Question #176685 in Calculus for tasnu

Question #176685

For the function below find the inverse.

a. 𝑓(π‘₯) = (π‘₯ βˆ’ 2) 5 + 3

b. 𝑔(π‘₯) = 4 π‘₯+2

c. β„Ž(π‘₯) = 4 βˆ’ √4π‘₯ 3 2

d. 𝑓(π‘₯) = 4π‘₯ 3 + 2


1
Expert's answer
2021-03-30T16:08:43-0400

a). y=8xβˆ’10y=8x-10 . We get the following inverse: x=18(y+10)x=\frac{1}{8}(y+10)

b). y=4x+2y=4x+2 . We obtain the inverse: x=14(yβˆ’2)x=\frac{1}{4}(y-2)

c). y=4βˆ’64xy=4-6\sqrt{4}x. The inverse is: x=164(4βˆ’y)x=\frac{1}{6\sqrt{4}}(4-y)

d). y=12x+2y=12x+2 . We get the inverse: x=112(yβˆ’2)x=\frac{1}{12}(y-2)


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