For the function below find the inverse.
a. 𝑓(𝑥) = (𝑥 − 2) 5 + 3
b. 𝑔(𝑥) = 4 𝑥+2
c. ℎ(𝑥) = 4 − √4𝑥 3 2
d. 𝑓(𝑥) = 4𝑥 3 + 2
a). y=8x−10y=8x-10y=8x−10 . We get the following inverse: x=18(y+10)x=\frac{1}{8}(y+10)x=81(y+10)
b). y=4x+2y=4x+2y=4x+2 . We obtain the inverse: x=14(y−2)x=\frac{1}{4}(y-2)x=41(y−2)
c). y=4−64xy=4-6\sqrt{4}xy=4−64x. The inverse is: x=164(4−y)x=\frac{1}{6\sqrt{4}}(4-y)x=641(4−y)
d). y=12x+2y=12x+2y=12x+2 . We get the inverse: x=112(y−2)x=\frac{1}{12}(y-2)x=121(y−2)
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