Answer to Question #176677 in Calculus for Joshua

Question

Determine the area of the region bounded by the given set of curves y=x^2+2, y=sin(x), x=2.

Answer 1

$Assuming\ it\ is\ also\ bounded\ by\ x=0,\$

$\int_{0}^{2}{x^2+2-\sin{\left(x\right)}\ dx}$

$\frac{x^3}{3}+2x+\cos{\left(x\right)}\ \ \left(0,\ 2\right)$

$\frac{8}{3}+4+\cos{\left(2^c\right)}-1$

$5.2505\ square\ units$