Answer to Question #176669 in Calculus for Joshua

Question #176669

Find the area of the region bounded by y=3-e^-x, the x-axis, x=2 and the y-axis.

Expert's answer

$؞ area=∫_0^2(3-e^{-x} )dx$

$=[3x+e^{-x} ]_0^2$

$=6+e^{-2}=6.135$ square units of length

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