Answer to Question #176669 in Calculus for Joshua

Question #176669

Find the area of the region bounded by y=3-e^-x, the x-axis, x=2 and the y-axis.

Expert's answer

"\u061e area=\u222b_0^2(3-e^{-x} )dx"

"=[3x+e^{-x} ]_0^2"

"=6+e^{-2}=6.135" square units of length

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