Find the area of the region bounded by y=3-e^-x, the x-axis, x=2 and the y-axis.
؞area=∫02(3−e−x)dx؞ area=∫_0^2(3-e^{-x} )dx؞area=∫02(3−e−x)dx
=[3x+e−x]02=[3x+e^{-x} ]_0^2=[3x+e−x]02
=6+e−2=6.135=6+e^{-2}=6.135=6+e−2=6.135 square units of length
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