Answer to Question #176669 in Calculus for Joshua

Question

Find the area of the region bounded by y=3-e^-x, the x-axis, x=2 and the y-axis.

Answer 1

$؞ area=∫_0^2(3-e^{-x} )dx$

$=[3x+e^{-x} ]_0^2$

$=6+e^{-2}=6.135$ square units of length