Compute the area bounded by the curve r=sin2(∅) for 0≤∅≤ π/2.
Area bounded by the curve r=sin2(∅) for 0≤∅≤ π/2.
We integrate r=sin2(∅) with limits from 0 to
π/2
∫0π2r=sin2(∅)\int_0^{π\over2} r=sin2(∅)∫02πr=sin2(∅)
On solving , and putting limits
=[cos(2∅)2]0π=[{cos(2∅)\over2} ]_0^\pi =[2cos(2∅)]0π
=[−(−12)]−[−(12)]=[-({-1\over2})]-[-({1\over2})]\\=[−(2−1)]−[−(21)]
=1=1=1 ......answer
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