Determine all the points on the curve
y = 2x ^ 3 + 3x ^ 2 - 18x + 3 where the slope of the tangent line is -6.
y=2x3+3x2−18x+3y = 2x^3+3x^2-18x+3y=2x3+3x2−18x+3
y′(x0) is the slope of the tangent at the point x0y'(x_0) \text{ is the slope of the tangent at the point }x_0y′(x0) is the slope of the tangent at the point x0
y′(x)=6x2+6x−18y'(x)= 6x^2+6x-18y′(x)=6x2+6x−18
6x2+6x−18=−66x^2+6x-18 =-66x2+6x−18=−6
x2+x−2=0x^2+x-2 =0x2+x−2=0
x1=1;x2=−2x_1=1;x_2=-2x1=1;x2=−2
Answer:x1=1;x2=−2x_1=1;x_2=-2x1=1;x2=−2
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