A particle moves in the xy-plane with the position given by the parametric equations:
x = t3 - t2 - 9t +9
y = 2 - t
Find the location of the particle when t = 1.
(_, _)
x(1)=13−12−9⋅1+9=0y(1)=2−1=1x(1) = 1^3 - 1^2 - 9 \cdot 1 + 9 = 0 \\ y(1) = 2 -1 = 1x(1)=13−12−9⋅1+9=0y(1)=2−1=1
Answer: (0, 1)
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