∫ √(1 + cos θ) dθ
Let us evaluate the integral
"\\int \\sqrt{1+\\cos\\Theta}d\\Theta=\\int \\sqrt{2\\cos^2\\frac{\\Theta}{2}}d\\Theta=\n2\\sqrt{2}\\int \\cos\\frac{\\Theta}{2}d\\frac{\\Theta}{2}=2\\sqrt{2}\\sin\\frac{\\Theta}{2}+C"
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