∫ √(1 + cos θ) dθ
Let us evaluate the integral
∫1+cosΘdΘ=∫2cos2Θ2dΘ=22∫cosΘ2dΘ2=22sinΘ2+C\int \sqrt{1+\cos\Theta}d\Theta=\int \sqrt{2\cos^2\frac{\Theta}{2}}d\Theta= 2\sqrt{2}\int \cos\frac{\Theta}{2}d\frac{\Theta}{2}=2\sqrt{2}\sin\frac{\Theta}{2}+C∫1+cosΘdΘ=∫2cos22ΘdΘ=22∫cos2Θd2Θ=22sin2Θ+C
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