Question #174631

Evaluate the integral of (sin x + cosx)² dx


Expert's answer

∫(sin⁡x+cos⁡x)2 dx=∫sin⁡2x+2sin⁡xcos⁡x+cos⁡2x dx=∫(sin⁡2x+cos⁡2x) dx+∫2sin⁡xcos⁡x dx=∫dx+∫2sin⁡x d(sin⁡x)=x+sin⁡2x+C\int (\sin x + \cos x)^2\,dx = \\ \int \sin^2 x + 2\sin x\cos x + \cos^2 x\,dx = \\ \int (\sin^2 x + \cos^2 x) \,dx + \int 2\sin x \cos x \,dx = \\ \int dx + \int 2\sin x \,d(\sin x) = \\ x + \sin^2 x + C


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