Question #174631

Evaluate the integral of (sin x + cosx)² dx


1
Expert's answer
2021-03-30T13:47:18-0400

(sinx+cosx)2dx=sin2x+2sinxcosx+cos2xdx=(sin2x+cos2x)dx+2sinxcosxdx=dx+2sinxd(sinx)=x+sin2x+C\int (\sin x + \cos x)^2\,dx = \\ \int \sin^2 x + 2\sin x\cos x + \cos^2 x\,dx = \\ \int (\sin^2 x + \cos^2 x) \,dx + \int 2\sin x \cos x \,dx = \\ \int dx + \int 2\sin x \,d(\sin x) = \\ x + \sin^2 x + C


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