Question #174629

Evaluate the integral of xe^(x²) dx from 0 to 1


1
Expert's answer
2021-03-30T08:06:18-0400

01xex2dx=[x2=u,2xdx=du,xdx=12du,11,00]==1201eudu=12eu01=e12\int_0^1xe^{x^2}dx = [x^2 = u, 2xdx=du, xdx=\cfrac{1}{2}du, 1\to1,0\to0] =\\ =\cfrac{1}{2}\int_0^1e^udu = \cfrac{1}{2}e^u|_0^1 = \cfrac{e-1}{2}


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