Question #174622

Evaluate the integral of sin2x dx/(2+sin² x)


1
Expert's answer
2021-03-29T14:01:54-0400

Ans:-

Sin2x2+sin2xdx\int\dfrac{Sin2x}{2+sin^2x}dx


Sin2x=2×(Sinx)×(Cosx)Sin2x=2\times(Sinx)\times(Cosx)

put 2+Sin2x=t2Sinxcosxdx=dt2+Sin^2x=t \Rightarrow 2Sinxcosxdx=dt


dtt=lnt+C\int\dfrac{dt}{t}=lnt +C


ln(2+Sin2x)+C\Rightarrow ln(2+Sin^2x)+C


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