Answer to Question #174613 in Calculus for Phyroe

Question

Evaluate the integral of (3x² - 4 +1) dx

Answer 1

We have to find integral $\int$ (3x² - 4 + 1) dx

( since we know that $\int$ xⁿ dx = $\frac{x^n +1}{n+1}$ )

therefore,

$\int$ (3x² - 4 + 1) dx

= $\int$ (3x² - 3) dx

= $\int$ 3x² dx + $\int$-3 dx

= 3$\int$x² dx - 3$\int$1 dx

= 3$\frac{x^3}{3}$ - 3x + c

= x³ - 3x + c

where c is any constant