Question #172760

e) lim_((x y) to (0 0)) (sin x)/(y) exists.


Expert's answer

Solution:

lim(x,y)(0,0)(sin(x)y)\lim _{\left(x,\:y\right)\to \left(0,\:0\right)}\left(\frac{\sin \left(x\right)}{y}\right)

We calculate limit along two different paths.

Along x=0:x=0:

lim(x,y)(0,0)(sin(0)y)\lim _{\left(x,\:y\right)\to \left(0,\:0\right)}\left(\frac{\sin \left(0\right)}{y}\right)=0=0

Along x=y:x=y:

lim(y,y)(0,0)(sin(y)y)\lim _{\left(y,\:y\right)\to \left(0,\:0\right)}\left(\frac{\sin \left(y\right)}{y}\right)=1=1

Since, they are unequal, limit diverges or does not exist.


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