Question #169769

z=f(x-y)


1
Expert's answer
2021-03-09T05:35:40-0500

We have,


z = f(x-y)


Partially derivate w.r.t 'x'

δzδx=f(xy)\dfrac{\delta z}{\delta x} = f'(x-y)


Now, partially derivate w.r.t 'y'


δzδy=f(xy)\dfrac{\delta z}{\delta y} = -f'(x-y)


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