Question

Differentiate the function.
y = 2x log7(√x)

Answer 1

y' = 2 log₇(√x) + 2x *(log₇(√x))' = log₇(x) + 2x* 1/(ln7 *√x) * 1/(2√x) = log₇(x) + 1/ln7 = log₇(x) + log₇(e) = log 7 (xe)