Differentiate the function.f(x) = log[sub]9[/sub](xe[sup]x[/sup])
f'(x) = [(xex)ln9]-1* (xex)' = ex(1 +x)* [(xex)ln9]-1= (1+x)/(x ln9)
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!