Intergate completely.
∫(4x^5-15x^4-x^3+12x^2+2x+3)/(x^2-3x-2)dx
Answer is
x4−x3−x2+ln∣(x−32)2+14∣+Cx^{4}-x^{3}-x^{2}+\ln \left|\left(x-\frac{3}{2}\right)^{2}+\frac{1}{4}\right|+Cx4−x3−x2+ln∣∣(x−23)2+41∣∣+C
Explanation below
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