Evaluate the ∫1-siny dy/y+cosy
Solution
I=∫1−sinyy+cosydyI=\int \frac{1-sin y}{y+cos y}dyI=∫y+cosy1−sinydy
Substitution x = y+cos y, dx = 1-sin y:
I=∫dxx=ln∣x∣+C=ln∣y+cosy∣+CI=\int \frac{dx}{x}=ln|x|+C=ln|y+cos y|+CI=∫xdx=ln∣x∣+C=ln∣y+cosy∣+C
Answer
∫1−sinyy+cosydy=ln∣y+cosy∣+C\int \frac{1-sin y}{y+cos y}dy=ln|y+cos y|+C∫y+cosy1−sinydy=ln∣y+cosy∣+C
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