Evaluate the ∫1-siny dy/y+cosy
Solution
"I=\\int \\frac{1-sin y}{y+cos y}dy"
Substitution x = y+cos y, dx = 1-sin y:
"I=\\int \\frac{dx}{x}=ln|x|+C=ln|y+cos y|+C"
Answer
"\\int \\frac{1-sin y}{y+cos y}dy=ln|y+cos y|+C"
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