Question #162030

Evaluate the ∫1-siny dy/y+cosy


1
Expert's answer
2021-02-24T12:37:28-0500

Solution

I=1sinyy+cosydyI=\int \frac{1-sin y}{y+cos y}dy

Substitution x = y+cos y,  dx = 1-sin y:

I=dxx=lnx+C=lny+cosy+CI=\int \frac{dx}{x}=ln|x|+C=ln|y+cos y|+C

Answer

1sinyy+cosydy=lny+cosy+C\int \frac{1-sin y}{y+cos y}dy=ln|y+cos y|+C

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