Question #162029

Evaluate the ∫(t³+3t/t²+1)dt


1
Expert's answer
2021-02-24T12:30:34-0500

Solution:

ApplytheSumRule:f(x)±g(x)dx=f(x)dx±g(x)dx\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx


t3dt=t44\int t^3dt=\dfrac{t^4}{4}


3tt2dt=3lnt\int \dfrac{3t}{t^2}dt=3ln|t|


1dt=t\int 1dt=t


t3dt+3tt2dt+1dt=t44+3lnt+t+C\int \:t^3dt+\int \frac{3t}{t^2}dt+\int \:1dt=\dfrac{t^4}{4}+3ln|t|+t+C


Answer:

t44+3lnt+t+C\dfrac{t^4}{4}+3ln|t|+t+C


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