Question #162023

Evaluate the ∫(x+2/x-2)dx


1
Expert's answer
2021-02-25T05:04:13-0500

x+2x2dx=x2+4x2dx=x2x2dx+4x2dx=dx+41x2dx\int \frac{x+2}{x-2} dx = \int \frac{x-2+4}{x-2} dx = \int \frac{x-2}{x-2} dx + \int \frac{4}{x-2} dx = \int dx +4 \int \frac{1}{x-2} dx =x+4lnx2+C= x + 4ln\mid x-2 \mid + C


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