Evaluate the ∫(x+2/x-2)dx
∫x+2x−2dx=∫x−2+4x−2dx=∫x−2x−2dx+∫4x−2dx=∫dx+4∫1x−2dx\int \frac{x+2}{x-2} dx = \int \frac{x-2+4}{x-2} dx = \int \frac{x-2}{x-2} dx + \int \frac{4}{x-2} dx = \int dx +4 \int \frac{1}{x-2} dx∫x−2x+2dx=∫x−2x−2+4dx=∫x−2x−2dx+∫x−24dx=∫dx+4∫x−21dx =x+4ln∣x−2∣+C= x + 4ln\mid x-2 \mid + C=x+4ln∣x−2∣+C
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