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Answer to Question #16186 in Calculus for akansha
Question #16186
if xy=1 then y^2 +dy/dx is =??
Expert's answer
xy=1
y=1/x
dy/dx=-1/x^2
-1/x^2=-y^2
y^2-dy/dx=y^2-y^2=0
y=1/x
dy/dx=-1/x^2
-1/x^2=-y^2
y^2-dy/dx=y^2-y^2=0
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