Question #161400

A particle moves along the x-axis so that at time t ≥ 0 its position is given by v(t) = 6t^2 - 84t -90. Determine all intervals when the acceleration of the particle is negative.


Expert's answer

The acceleration a(t)=12t−84a(t)=12t-84

12t−84<012t-84<0

12t<8412t<84

t<7t<7

Answer: the acceleration of the particle is negative when t<7.t<7.


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