Find the first six terms of the sequence. a1 = -4, an = an-1 + 7
a1=−4a_1=-4a1=−4
a2=a1+7=−4+7=3a_2=a_1+7=-4+7=3a2=a1+7=−4+7=3
a3=a2+7=3+7=10a_3=a_2+7=3+7=10a3=a2+7=3+7=10
a4=a3+7=10+7=17a_4=a_3+7=10+7=17a4=a3+7=10+7=17
a5=a4+7=17+7=24a_5=a_4+7=17+7=24a5=a4+7=17+7=24
a6=a5+7=24+7=31a_6=a_5+7=24+7=31a6=a5+7=24+7=31
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