Question #159568

For each of the following functions, respond to the given prompts. Show all work that leads to your responses. 

Given: 𝑓(π‘₯) = 3π‘₯^3 βˆ’ 18π‘₯^2 βˆ’ 45π‘₯ + 10 

a. On what interval(s), is 𝑓(π‘₯) increasing? Show all work and explain


b. At what value(s) of π‘₯ does 𝑓(π‘₯) have a relative minimum? Show all work and explain


c) On what interval(s), is 𝑓(π‘₯) decreasing and concave up? Show all work and explain


Expert's answer

Given: 𝑓(π‘₯)=3π‘₯3βˆ’18π‘₯2βˆ’45π‘₯+10𝑓(π‘₯) = 3π‘₯^3 βˆ’ 18π‘₯^2 βˆ’ 45π‘₯ + 10

a. On what interval(s), is 𝑓(π‘₯) increasing?

fβ€²(x)>0f'(x) > 0

9x2βˆ’36xβˆ’45=9(xβˆ’4xβˆ’5)=9(xβˆ’5)(x+1)>09x^2-36x-45 = 9(x-4x-5) = 9(x-5)(x+1) > 0

function is increasing where (βˆ’βˆž;βˆ’1)βˆͺ(5;∞)(-\infin; -1)\cup (5; \infin)

b. At what value(s) of π‘₯ does 𝑓(π‘₯) have a relative minimum?

We say that f(x) has a relative minimum at x = c if f(x)β©Ύf(c)f(x) \geqslant f(c) for every x in some open interval around x=cx = c x = -1 is relative minimum

c) On what interval(s), is 𝑓(π‘₯) decreasing and concave up?

fβ€²(x)<0f'(x) < 0

9x2βˆ’36xβˆ’45=9(xβˆ’4xβˆ’5)=9(xβˆ’5)(x+1)<09x^2-36x-45 = 9(x-4x-5) = 9(x-5)(x+1) < 0

function is decreasing where (βˆ’1;5)(-1;5)

  • When the second derivative is positive, the function is concave upward.

fβ€²β€²(x)=18xβˆ’36>0f''(x) = 18x-36 > 0

x>2x > 2

function is concave up where (2;∞)(2; \infin)


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