Determine the limit when x goes to 0 of (sin(1/x)) if it exists.
The limit does not exist.
h=1x, x→0, h→∞,h=\frac 1x, ~x\rightarrow0,~h\rightarrow \infin,h=x1, x→0, h→∞,
limx→0sin1x=limh→∞sin(h).\lim\limits_{x\rightarrow0}sin\frac 1x=\lim\limits_{h\rightarrow\infin}sin(h).x→0limsinx1=h→∞limsin(h).
As hhh gets bigger, sin(h)sin(h)sin(h) keeps fluctuating between -1
and 1. It never tends towards anything, or stops fluctuating at any point.
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