Eliminate a & b from az+b=a²x+y
Given equation is
az+b=a²x+yaz+b=a²x+yaz+b=a²x+y
Differentiating w.r.t. x and y, we get
ap=a2ap = a^2ap=a2
and aq=1→a=1qaq = 1 \to a = \large\frac{1}{q}aq=1→a=q1
and hence pq=1pq = 1pq=1 is the required first order PDE
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