Find the differential of y=(x+a)²
differential, dy = y' dx
Since "a" is a constant.
using chain rule to find y'
dydx=dydu×dudx{dy \over dx} = {dy \over du} × {du \over dx}dxdy=dudy×dxdu
Let u=x+a=x + a=x+a
then dudx=1{du \over dx} = 1dxdu=1
y = u²
dydu=2u{dy \over du} = 2ududy=2u
∵\because∵ dydx=2u.1{dy \over dx} = 2u . 1dxdy=2u.1
dy=2(x+a)dxdy =2(x +a)dxdy=2(x+a)dx
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