Answer to Question #154160 in Calculus for Alex Mann

Question

how to find the derivative of 2x-9/(3x+4)^2

Answer 1

$(2x-\frac{9}{(3x+4)^2})' = (2x-9*(3x+4)^{-2})' = 2+18*(3x+4)^{-3}*(3x)' =\\= 2+\frac{54}{(3x+4)^3}$