Question #154160

how to find the derivative of 2x-9/(3x+4)^2


1
Expert's answer
2021-01-07T13:44:17-0500

(2x−9(3x+4)2)′=(2x−9∗(3x+4)−2)′=2+18∗(3x+4)−3∗(3x)′==2+54(3x+4)3(2x-\frac{9}{(3x+4)^2})' = (2x-9*(3x+4)^{-2})' = 2+18*(3x+4)^{-3}*(3x)' =\\= 2+\frac{54}{(3x+4)^3}


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