Answer to Question #154160 in Calculus for Alex Mann

Question #154160

how to find the derivative of 2x-9/(3x+4)^2

Expert's answer

"(2x-\\frac{9}{(3x+4)^2})' = (2x-9*(3x+4)^{-2})' = 2+18*(3x+4)^{-3}*(3x)' =\\\\= 2+\\frac{54}{(3x+4)^3}"

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