Question

y=3z+4x^2

Answer 1

We have, $y=3z+4x^2$

Differentiating wrt x we get,

$\frac{dy}{dx}=3\frac{dz}{dx}+8x\\$

Therefore, the value of $\frac{dy}{dx}$ is,

$$\frac{dy}{dx}=3\frac{dz}{dx}+8x$$