Question #153484

Values of f(x) are given at a, b, and c. Show that the maximum is obtained by

f(a) (b^2 - c^2) + f(b) (c^2 - a^2) + f(c) (a^2 - b^2)

x = -----------------------------------------------------------------

f(a) (b - c) + f(b) (c - a) + f(c) (a - b)


Expert's answer

If the condition of the task is:

the maximum is obtained by

x=f(a)(b2−c2)+f(b)(c2−a2)+f(c)(a2−b2)f(a)(b−c)+f(b)(c−a)+f(c)(a−b)x=\frac{f(a) (b^2 - c^2) + f(b) (c^2 - a^2) + f(c) (a^2 - b^2) }{f(a) (b - c) + f(b) (c - a) + f(c) (a - b)}

then:

we don't know what is f(x)f(x), and we can put any values for f(a),f(b),f(c)f(a), f(b),f(c) ;

and we cannot say what value is of fmax(x)f_{max}(x).

So, we have some abstract formula.

That's why I think that it should be some other additional condititions for f(x)f(x) .


For example:

a=1,b=2,c=3a=1, b=2, c=3

Since we don't know what is f(x)f(x), we can put any values for f(a),f(b),f(c)f(a), f(b), f(c)

For example:

f(a)=10,f(b)=20,f(c)=30f(a)=10, f(b)=20, f(c)=30

So, we get:

x=10(4−9)+20(9−1)+30(1−4)10(2−3)+20(3−1)+30(1−2)→∞x=\frac{10 (4 - 9) + 20 (9 - 1) + 30 (1 - 4) }{10 (2 - 3) + 20 (3 - 1) + 30 (1 - 2)}\to \infin

But, again, a function f(x)f(x) is unknown for us. And we have not to say about the given value of xx or value of fmax(x)f_{max}(x).

We have to know value(s) of xx when f′(x)=0f'(x)=0 , but it is impossibile having the given condititions of the task.


LATEST TUTORIALS
APPROVED BY CLIENTS