Kinematic equations for objects thrown downwards
We assume here that acceleration equals −a=−10m/s2 (with the positive direction upward).
v=v0+at
y=y0+v0t+2at2
v2=v02+2a(y−y0)
Given y0=150m,v0=−5m/s,a=−10m/s2
y1=0:0=150−5t−210t2
t2+t−30=0
t1=−6,t2=5 Since t≥0, we take t2=5s.
v(5)=−5−10(5)=−55(m/s) The stone will fall down the ground after 5 seconds. Its velocity will be 55 m/s when it falls down the ground.
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