Question #152392
the acceleration due to gravity on the planet Calcllceara is -10m/s^2. A stone is thrown downwards with a speed of 5 m/s from the upper observation deck of the Base Camp Alpha Tower, 150 m above the ground
1
Expert's answer
2020-12-22T18:35:42-0500

Kinematic equations for objects thrown downwards

We assume here that acceleration equals a=10m/s2-a=-10 m/s^2  (with the positive direction upward).


v=v0+atv=v_0+at

y=y0+v0t+at22y=y_0+v_0t+\dfrac{at^2}{2}


v2=v02+2a(yy0)v^2=v_0^2+2a(y-y_0)



Given y0=150m,v0=5m/s,a=10m/s2y_0=150m, v_0=-5m/s, a=-10m/s^2



y1=0:0=1505t10t22y_1=0:0=150-5t-\dfrac{10t^2}{2}

t2+t30=0t^2+t-30=0

t1=6,t2=5t_1=-6, t_2=5

Since t0,t\geq0, we take t2=5s.t_2=5s.


v(5)=510(5)=55(m/s)v(5)=-5-10(5)=-55(m/s)

The stone will fall down the ground after 5 seconds. Its velocity will be 55 m/s when it falls down the ground.



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