i)Velocity after 5 sec is: V=V0+at,
V0=0, V=5a
ii) Average velocity Vavr= Stotal/ttotal
S=at2/2. In our case t=10 : Vavr=at2/(2×10), Vavr=5a
iii)acceleration after 2 sec, we can derive it from the formual:V=V0+at, from here we find a, a=V/t, a=V/2.
iv) average acceleration from t=2 to t=4 can be found by (a2+a4)/2.
a2=V2/2, a4=V4/4. So
aavr=(V2/2+V4/4)/2,
aavr=(2V2+V4)/8
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