Question

Suppose a person standing at the top of a building 112 ft high throws a ball vertically upward
with an initial velocity of 96 ft/sec.
(a) Find the velocity of the ball at time

Answer 1

The formula of the velocity of the ball thrown vertically upward is:

V(t)=V₀-gt

So in our case initial velocity V₀=96ft/sec;

g=32ft/sec;

General equation is:V(t)=96-32t;

the answer is:

V(t)=96-32t.