Answer to Question #147658 in Calculus for liam donohue

Question

∫102e8x−4e4xdx=

Answer 1

$\int(102e^{8x}-4e^{4x})dx\\ \frac{102}{8}e^{8x}-\frac{4}{4}e^{4x}+c\\ \frac{102}{8}e^{8x}-e^{4x}+c$