∫−4−7(x−1+3x)dxSolution:[x1+11+1−1x+3x1+11+1]−4−7[x22−1x+3x22]−4−7[x22+3x22−x]−4−7[4x22−x]−4−7[4x2−2x2]−4−7(4(−7)2−2(−7)2)−(4(−4)2−2(−4)2)105−36=69\int_{-4}^{-7} (x - 1 + 3x)dx\\ Solution:\\ \left[\LARGE{\frac{x^{1+1}}{1 + 1} - 1x + 3\frac{x^{1+1}}{1 +1}}\right]_{-4}^{-7}\\ \left[\LARGE{\frac{x^{2}}{2} - 1x + 3\frac{x^{2}}{2}}\right]_{-4}^{-7}\\ \left[\LARGE{\frac{x^{2}}{2} + 3\frac{x^{2}}{2} -x}\right]_{-4}^{-7}\\ \left[\LARGE{4\frac{x^{2}}{2} -x}\right]_{-4}^{-7}\\ \left[\LARGE{\frac{4x^2 - 2x}{2}}\right]_{-4}^{-7}\\ \left(\LARGE{\frac{4(-7)^2 - 2(-7)}{2}}\right) - \left(\LARGE{\frac{4(-4)^2 - 2(-4)}{2}}\right)\\ 105 - 36\\ = 69∫−4−7(x−1+3x)dxSolution:[1+1x1+1−1x+31+1x1+1]−4−7[2x2−1x+32x2]−4−7[2x2+32x2−x]−4−7[42x2−x]−4−7[24x2−2x]−4−7⎝⎛24(−7)2−2(−7)⎠⎞−⎝⎛24(−4)2−2(−4)⎠⎞105−36=69
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments