Question

Evaluate the definite integral

∫728x−−√dx

Answer 1

Evaluate the definite integral:

$\int^7_2\sqrt{8x} dx$ = $2\sqrt{2}\int^7_2 \sqrt{x}dx=2\sqrt{2}(\frac{2\sqrt{x^3}}{3}\mid^7_2)=2\sqrt{2}(\frac{2\sqrt{7^3}}{3}-\frac{2\sqrt{2^3}}{3})$

$2\sqrt{2}(\frac{2\sqrt{7^3}}{3}-\frac{2\sqrt{2^3}}{3})=\frac{28\sqrt{14}-8}{3}$