Answer to Question #143656 in Calculus for 1805040444b

Question

Find the derivative f 0 m(x) of the following function with respect to x:

fm(x) = (mΣ n=1 n^x · x^n )^2

Answer 1

$f_m(x)=\big(\displaystyle\sum_{ n=1}^m(n^x\cdot x^n)\big)^2$

$f_m'(x)=\bigg(\big(\displaystyle\sum_{n=1}^m(n^x\cdot x^n)\big)^2\bigg)'=$

$=2\cdot\displaystyle\sum_{n=1}^m(n^x\cdot x^n)\cdot\displaystyle\sum_{n=1}^m\big(\ln(n)\cdot n^x\cdot x^n+n^{x+1}\cdot x^{n-1}\big)$