Question

Evaluate lim┬((x,y)→(6,2))⁡〖(x^2-3xy)/(x-3y)〗

Answer 1

We have to find

$$\lim_{(x,y)\rightarrow (6,2)}\frac{x^2-3xy}{x-3y}\\ \implies \lim_{(x,y)\rightarrow (6,2)}\frac{x(x-3y)}{x-3y}\\ \implies \lim_{(x,y)\rightarrow (6,2)}x=6$$