Evaluate the integral (upper limit 4 lower limit 1) dx/[2sqrt(x)*(1+sqrtx)^2] I have substituted sqrt x for u and end up with the integral du/(1+u)^2 (still from 1 to 4) but now Im stuck..I have tried the integral of du/(1+u)^2 = (1+u)^-2 but that doesnt work. I will be so grateful if someone could just explain where Im going wrong. Thank you. ( the coreect answer must be one of the following ln28: 3/4 : -3/4 or 1/6
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