"\\displaystyle\n\n\n f(x) = \\frac{2}{x^9} = 2x^{-9}\\\\\n\nf'(x) = -18x^{-10}\\\\\n\nf'(2) = -18\\times 2^{-10} = \\frac{-9}{512}\\\\\n\n\nf'(-3) = -18\\times (-3)^{-10} = \\frac{-2}{3^8} = \\frac{-2}{6561}"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment